Rotate Image medium
Problem Statement
You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise).
You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.
Example 1:
Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
Output: [[7,4,1],[8,5,2],[9,6,3]]
Example 2:
Input: matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]
Output: [[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]
Steps and Explanation
The key to solving this problem efficiently and in-place is to understand the relationship between the indices of elements before and after rotation. We can achieve the rotation in four steps:
-
Transpose: We first transpose the matrix. Transposing a matrix swaps rows and columns. This means element at
matrix[i][j]
becomesmatrix[j][i]
. -
Reverse Columns: After transposing, we reverse each row (column in the original matrix). This completes the 90-degree clockwise rotation.
Let's illustrate with Example 1:
Original Matrix:
[[1, 2, 3],
[4, 5, 6],
[7, 8, 9]]
Step 1: Transpose
[[1, 4, 7],
[2, 5, 8],
[3, 6, 9]]
Step 2: Reverse Columns (rows after transpose)
[[7, 4, 1],
[8, 5, 2],
[9, 6, 3]]
Code (C#)
using System;
public class Solution {
public void Rotate(int[][] matrix) {
int n = matrix.Length;
// Transpose the matrix
for (int i = 0; i < n; i++) {
for (int j = i; j < n; j++) {
int temp = matrix[i][j];
matrix[i][j] = matrix[j][i];
matrix[j][i] = temp;
}
}
// Reverse each row
for (int i = 0; i < n; i++) {
Array.Reverse(matrix[i]);
}
}
}
Complexity Analysis
-
Time Complexity: O(n^2), where n is the dimension of the square matrix. We iterate through the matrix twice (once for transposition and once for reversal).
-
Space Complexity: O(1). The rotation is done in-place; we don't use any extra space proportional to the input size. We only use a constant amount of extra space for temporary variables.