Rotate Image medium
Problem Statement
You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise).
You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.
Example 1:
Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
Output: [[7,4,1],[8,5,2],[9,6,3]]
Example 2:
Input: matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]
Output: [[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]
Steps
The core idea is to perform the rotation in four steps:
-
Transpose: First, transpose the matrix. Transposing a matrix swaps rows and columns. Element at
matrix[i][j]
becomesmatrix[j][i]
. -
Reverse Columns: After transposing, reverse each row (column in the original matrix). This completes the 90-degree clockwise rotation.
Explanation
Let's illustrate with a 3x3 matrix:
Original Matrix:
1 2 3
4 5 6
7 8 9
Step 1: Transpose
1 4 7
2 5 8
3 6 9
Step 2: Reverse each row
7 4 1
8 5 2
9 6 3
This is the 90-degree clockwise rotated matrix. This approach avoids the need for creating a new matrix, achieving in-place rotation.
Code (Java)
class Solution {
public void rotate(int[][] matrix) {
int n = matrix.length;
// Transpose the matrix
for (int i = 0; i < n; i++) {
for (int j = i; j < n; j++) {
int temp = matrix[i][j];
matrix[i][j] = matrix[j][i];
matrix[j][i] = temp;
}
}
// Reverse each row
for (int i = 0; i < n; i++) {
for (int j = 0; j < n / 2; j++) {
int temp = matrix[i][j];
matrix[i][j] = matrix[i][n - 1 - j];
matrix[i][n - 1 - j] = temp;
}
}
}
}
Complexity
- Time Complexity: O(n²) - We iterate through the matrix twice (transposing and reversing).
- Space Complexity: O(1) - The rotation is done in-place; we don't use any extra space proportional to the input size.